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feos wrote:
Looking at the recent edit in the pub description I want to ask FractalFusion: did you really listen to that solo? :D
I never thought much about that ending theme.
It is better than the noise in the level, but that's not saying much.
Actually, the whole thing makes me wonder if the sound is really just an emulator glitch.
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saomoore94 wrote:
Warp wrote:
AKheon wrote:
Based on a quick test, a single flawless victory screen wastes 107 frames. If you could take damage in under 107 frames, you would save time.
I wonder if the time wasted getting hit could be avoided by having both characters hit each other simultaneously, with the computer opponent losing on that hit. (It might not save time at all, or it might even lose time, but just an idea to try.)
I don't even know what your talking about.
Warp is wondering:
1) if both player and computer can be hit at the same time,
2) if the computer can be KOed at the same time,
3) if it saves time compared to the player getting hit only.
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Patashu wrote:
when yellow any% and yellow 'pi day' also start the same?
Technically, they don't quite start the same (the any% does not give the rival a name, but the pi day one does).
They also differ in glitch execution; the any% does not use arbitrary execution.
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New video: http://www.youtube.com/watch?v=E-d9mgo8FGk
There's still some hand-waving going on (statements such as "Set x=-1" are not valid) but it touches upon analytic methods, and the Riemann zeta function of course.
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http://en.wikipedia.org/wiki/Divergent_series
I can't really say much about this subject considering it is far afield for me. All I can say is there are credible theories out there that agree on 1+2+3+4+...=-1/12, complex analysis being one (note: when I say theory, I mean theory, not a wild guess or anything like that).
You could make an argument like: Let 1+2+3+4+...=T and 1+1+1+...=U. Then T+U=2+3+4+...=T-1, so U=-1. On the other hand, T-U=0+1+2+3+...=T, so U=0. This may fit into the idea of "you can prove anything with infinities". Or rather, something in the theory should be considered wrong (since most of us believe that a theory that proves that every number is equal to every other number is a bad theory). For example, any one of "1+2+3+4+...=T", "1+1+1+...=U", "T+U=2+3+4+...", "2+3+4+...=T-1", could very well be considered a wrong statement, and that would actually improve the theory.
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For me, Sonic the Hedgehog TASes have become so broken that it is very difficult, if not impossible, for me to be impressed by glitched runs anymore. Almost nothing in this TAS impressed me, so I voted no. Just my feeling that times have changed.
This TAS definitely should be published though, because it is an improvement to an already existing one.
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Is the battle RNG like in Black/White where it only advances when it needs to make a decision? If so, is it possible to manipulate better starting seeds before entering battle?
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nico30620, in the future, please indicate that the game is a hack if it is (I edited the title this time), and which game it is derived from. I seriously did not know that this game had anything to do with SMW or hacks until I saw kaizoman666's last sentence.
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Flip's post is assuming that you know that the host will only ever use either the random strategy or the Monty Hall strategy each round, even if you don't know which of the two is used. Without this assumption, the argument does not hold.
Let's say the player knows that the host uses the strategy of opening the goat door with probability p and the car door with probability 1-p, if the player initially selected a goat door. Expectation is player win=1, loss=0.
Exp(switch)=Prob(switch wins)/Prob(host opens goat)=[(2/3)p] / [1/3+(2/3)p]
Exp(stay)=Prob(stay wins)/Prob(host opens goat)=[1/3] / [1/3+(2/3)p]
Random strategy is p=0.5, Monty Hall is p=1, host always opens car door (mentioned in my previous post) is p=0. 0≤p<0.5 means that it is best to stay, and 0.5<p≤1 means that it is best to switch. p=0.5 is neutral.
- Player knows that host will always use strategies each round with 0.5≤p≤1 (as in Flip's post): Always switch.
- Player knows that host will always use strategies each round with 0≤p≤0.5: Always stay.
- Above two do not apply and no other information: 50% switch/stay.
Warp wrote:
My mind just refuses to accept that one single round (where a goat was revealed) can have different probabilities depending on what the host's strategy is over all rounds.
The host's strategy (even if it will be applied to all rounds), as applied to one round, is the host's one-round strategy. It can be complicated like "Play random strategy (p=0.5) with 30% probability, play Monty Hall (p=1) with 30% probability, open a goat door 10% of the time (p=0.1) with 30% probability, open a goat door 80% of the time (p=0.8) with 10% probability," but it is still a strategy used in one round.
Probability has a strange way of working that goes against intuition. In regards to the question "If you are playing one single round, and the host reveals a goat door, is it advantageous to change?", information (whether the player knows anything about what the host's strategy is or not) is very important to answer this question. It is possible for the statements:
- "It is advantageous to switch."
- "It is advantageous to stay."
both to be false (e.g. player has no clue of the host's strategy), since the advantageous strategy is to play a mixed strategy (50% switch/stay). Thinking that it is always the case that one of the two must be true is a false dilemma. Assuming that "advantageous" means "there is no better strategy", then it is also possible for both of the statements to be true (e.g. host plays random strategy p=0.5); in this case, all player strategies are equally advantageous.
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Warp wrote:
If you are playing one single round, and the host reveals a goat door, is it advantageous to change?
Let's say you don't know if the host opened the door randomly or knowingly. How would you even know, if nobody tells you? How do you know if you are in the standard Monty Hall setup, or in the randomized version? There's no way of knowing.
Let's also assume that the host is allowed to use any strategy whatsoever, not just the two strategies mentioned (random, and Monty Hall/always open goat door) and the player has no way of knowing. This becomes a game-theoretic question.
The player can never do worse than 50%. Flip a coin. Don't switch if heads, switch if tails. No matter what strategy the host does, given that the opened door is a goat, switching is either right or wrong. Assigning 50% probabilities to switch or not switch gives 50% success rate, no matter what.
On the other hand, the host can set it up so that the player can never do better than 50% (random door strategy).
So the solution based on these assumptions: Flip a coin. Don't switch if heads, switch if tails. 50% success rate always.
On the other hand, if the player knew exactly what the host's strategy was, then the player may gain an advantage. If the host's strategy gives a higher-than-50% success rate for switching (such as Monty Hall), then the player switches. If the host's strategy gives a lower-than-50% success rate for switching (such as, host always opens car door if player initially selected goat door), then the player does not switch.
Warp wrote:
More puzzlingly, even if you do know, why would that make any difference?
It's called strategy. It exists just about everywhere (we're on a gaming site, even).
Whether only one round is performed or not is irrelevant. Every round has a success probability, even when there is only one.
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For those wondering what the new improvement is, here is a video of the TAS from when HM04(Strength) is obtained (speeding up some long parts):
Link to video
By the way, if Charmander is chosen, as well as fighting Blastoise instead of Venusaur, one fights Exeggutor instead of Gyarados.
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I'm pretty sure that "the better of two endings" is a form of "best ending".
That being said, I think Braid's "ending" is glitched and doesn't qualify for best ending (doesn't that require collecting all stars or something?).
I also think that if a run's best ending is the fastest version, then no branch name is necessary (although it can be reflected in movie categories).
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I haven't watched anything, but there is a TAS on Nicovideo.
http://www.nicovideo.jp/watch/sm20299607
(...and so on. The above video is just the first part of the whole thing.)
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After obtaining Mega Punch and Mega Kick, what is the next opposing Pokemon not to be OHKOed? Answer: Lorelei's Lapras. In fact, it is the only opposing Pokemon after obtaining Mega Punch and Mega Kick not to be OHKOed.
I find this TAS pretty interesting, with all the strategies. However, I found it a bit strange to that both Blizzard and Metronome were used, since I thought Metronome would have covered everything that was required for Blizzard. It could be faster this way though.
HP_Power=(5*(v+2w+4x+8y)+Z)/2 + 31
where
* v is 1 if SpcIV>=8; otherwise 0,
* w is 1 if SpeIV>=8; otherwise 0,
* x is 1 if DefIV>=8; otherwise 0,
* y is 1 if AtkIV>=8; otherwise 0,
* Z=3 if SpcIV>=3; otherwise Z=SpcIV.
However, I have verified that it is possible for SpcIV=11 to have a higher max damage than SpcIV=12, 13, or 14, assuming all other IVs are the same and all other circumstances equal. So the above formula is incorrect. If anyone can verify the actual formula, that would be welcome.
(I swear I remember somewhere 6 years ago where it said that Z=SpcIV mod 4.)
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I watched this TAS just now. Interestingly, this hack remixes a lot of well-known video-game music pieces. However, the hack seems to drag on for too long. I noticed that reviews for this hack are mostly negative.
As for TAS quality, I'd say that the result is just as expected for a TAS that has 1771 rerecords where the game is a Super Mario World hack that lasts over an hour. I can explain which specific parts look bad from a TAS point of view, but I will only do it if asked.
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Interesting run. But I have a big question: Is it possible to use Pidgey instead of Abra? Considering Pidgey has a much shorter cry...
Other than that, I have a couple comments:
- 8:09: It is faster to have Rattata's Tail Whip hit instead of miss.
- 15:46: It is faster to walk in front of the Hiker only after going as far right as possible on the row above. (In this case, the Hiker only walks one step.)
This run is pretty well-done. There is also the luck-manipulation issue, but I'll let it pass. (I didn't do much better in my really old Pokemon Gold TAS either.)
By the way, the memory addresses given in the submission text are based on offset from C000 (main RAM/whatever it is called); e.g. 1A3F is treated in GB as well as VBA as DA3F.
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Quick translation:
Uncertainty of recording in DeSmuME.
The problem is I'm trying to make a TAS in desmume. To start, I record movie, make a TAS for a while, and then stop movie. When I come back later and press play movie which I want to overwrite, then once finished the movie is still working, but when I press stop movie again, it does not save what I have done last. I hope I explained well. If anyone can help me, I'd appreciate it.
linkerlee: To resume recording of a movie, load a savestate in read+write mode (not when the movie is finished). I don't know if this helps.
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Interesting that this hack was considered a very promising WIP hack just three years ago ( http://tasvideos.org/forum/viewtopic.php?t=10118 ). Unfortunately, it hasn't changed since then.
Personally, I think this hack is too short. It feels like one (perhaps large) zone of an unfinished game rather than a complete game. Furthermore, game-breaking glitches tend to take away from the presentation of a hack rather than add to it. I found the Sound Test to be more interesting than the game itself.
I'm pretty sure there are better Sonic hacks out there, like Sonic Megamix and Sonic ERaZor. That being said, I'm not familiar with all the Sonic hacks so I can't tell if there are any ones out there that are even better.
Edit: WST or got4n, could you upload a 60fps version of the TAS (not on Youtube)? The Youtube encode at 30fps messes up the bosses because of flickering.
