Posts for Randil

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I'm really glad you liked my movie mrlemonlame! Yes, manu manipulation goes really, really fast in this game, which makes this run really fast-paced. And I agree, some parts of this game are "what the crap am I supposed to do now???"-hard. :)
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This sounds very interesting. At the moment I can come up with at least two things that you should check out thoroughly: 1. What time to set the clock to when you start the game. This has a lot of impact on the game, so check out every factor that changes with the clock and try to choose the optimal time. You have probably already thought about this though. 2. Find out exactly how "luck" works in Pokemon Crystal, since most of the run will contain heavy luck manipulation. Find out how to avoid fights, get critical hits, good stats with your Pokemon etc... Besides that I can only say good luck with your run Joeno, I'll gladly watch the progress, so please keep us informed by posting a WIP! :)
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Yes, please upload it. That could come really in handy. Can the program handle other integers as well, other than 4?
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FODA wrote:
write 1337 for example.
Allright: 1337 = ((4?)?)? - ((((√4)?)?)?)? - 4! - 4 That one was a little tricky :)
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Dan_ wrote:
(2?)! + √2 is approximately 7, does that count?
Meeeh.... I'd say no, IMO the equation has to result in an integer to count. And (2?)! + √2 = 7,41 isn't really that close to 7 anyway. But this is just my opinion.
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Xaphan wrote:
Did you try one 1 Randil ???? :)
Not, yet, but here it is: 1 = (√√√((1!)?)!)? Okay, that's about it :) Xaphan wrote:
try the 2 2s challenge :)
Allright then: 0 = 2-2 1 = 2/2 2 = √(2*2) 3 = (√2*√2)? 4 = 2*2 5 = 2 + 2? 6 = 2? + 2? 7 isn't possible to write with just two 2's. At least I don't think so. Not as high as the 4 4's challenge :) Back to the 4 4's problem: 383 = (4!)? + (4?)? + 4! + 4 384 = (4! + (√4)?)? + 4 + √4 385 = (4! + (√4)?)? + 4 + (√4)? 386 = (4! + (√4)?)? + 4 + 4 387 = (4! + (√4)?)? + (√4)?*(√4)? 388 = (4! + (√4)?)? + (√4*√4)? 389 = (4!)? + (4?)? + 4! + 4? 390 = (4!)? + (√4)?*(√4)?*4? 391 = ([√4*√4]!)? + (4?+[√4]?)? 392 = (4!)? + (([(√4)?]?)? + √4)*4 393 = (4!)? + (([(√4)?]?)?+√4)*(√4)? 394 = (4!)? + (√4)? + (4?+[√4]?)? 395 = (4!)? + 4 + (4?+[√4]?)? 396 = (4!)? + (√4*√4)!*4 397 = (4!)? + ((√4)?)? + (4?+[√4]?)? 398 = (4! + (√4)?)? + √4*(4?) 399 = (4!)? + (4?)? + 44 400 = 4*4*(([(√4)?]?)? + 4) Yay, we're up to 400!
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381 = (4!)? + (4?)? + 4! + √4 382 = (4!)? + (4?)? + 4! + (√4)? 382 = (4!)? + (4?)? + 4! + 4 Oh, and just for fun, here's how far I got with 4 1's: 0 = 1 + 1 - 1 - 1 1 = 1*1*1*1 2 = 1*1*1 + 1 3 = 1*1 + 1 + 1 4 = 1 + 1 + 1 + 1 5 = (1+1)? + 1 + 1 6 = (1+1)? + (1+1)? 7 = (1+1+1)? + 1 8 = 11 - (1+1)? 9 = 11 - 1 - 1 10 = 11 - 1*1 11 = 11*1*1 12 = 11 + 1*1 13 = 11 + 1 + 1 14 = 11 + (1+1)? 15 = ([(1+1)?]?)? - ((1+1)?)? Perhaps all of this is a little off topic, but since we've come so far with 4's, perhaps we should try other integers as well.
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Theoretically, you could go on forever, since there is no number that is to high to write with 4 4's. With just one 4 you could get amazingly high numbers, for example, ((4?)?)! = 1,27e+73, but I doubt we will go that far with this :p 379 = (4!)? + (4?)? + (√4*√4)! 380 = (4!)? +(4+4)*4?
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(4!)? is very useful when you get close to 300 since (4!)? = 24? = 300 295 = (4!)? - 4 -4/4 296 = (4!)? - (4*4)/4 297 = (4!)? - √4 - (4/4) 300 = (4!)? + (√4*√4) - 4 301 = (4!)? + (√4*√4)/4 302 = (4!)? + (4+4)/4 303 = (4!)? + 4 + 4/4 304 = (4!)? +4 +4 -4 305 = (4!)? +4 + 4/4 306 = (4!)? + √4 + √4 + √4 307 = (4!)? + √4 + √4 + (√4)? 308 = (4!)? +4 + √4 + √4 309 = (4!)? + (√4)? + (√4)? + (√4)? 310 = (4!)? + 4 + 4 + √4 311 = (4!)? + 4 + 4 + (√4)? 312 = (4!)? + 4 + 4 + 4 313 = (4!)? + 4*4 - (√4)? 314 = (4!)? + 4*4 - √4 315 = (4!)? + 4? +√4 + (√4)? 316 = (4!)? + (√4*√4)*4 317 = (4!)? + 4! - 4 - 4 318 = (4!)? + 4*4 + √4 319 = (4!)? + 4*4 + (√4)? 320 = (4!)? + 4*4 + 4 321 = (4!)? + (√4 + √4 + √4)? 322 = (4!)? + 4! - 4/√4 323 = (4!)? + 4! - 4/4 324 = (4!)? + 4! + 4 - 4 325 = (4!)? + 4! + 4/4 326 = (4!)? + 4! + 4/√4 327 = (4! + 4/4)? + √4 328 = (4! + 4/4)? + (√4)? 329 = (4! + 4/4)? + 4 330 = (4!)? + (√4*√4)?*(√4)? 331 = (4!)? + 4! + 4 + (√4)? 332 = (4!)? + 4! + 4 + 4 333 = (4!)? + (4+4)? - (√4)? 334 = (4!)? + (4+4)? - √4 335 = (4! + √4)? -4*4 336 = (4!)? + (4 + √4 + √4)? 337 = (4! + √4)? - 4? - 4 338 = (4! + √4)? - 4? - (√4)? 339 = (4! + √4)? - 4? - √4 340 = (4!)? + 44 - 4 341 = (4!)? + 44 - (√4)? 342 = (4!)? + 44 - √4 343 = (4! + √4)? - 4 - 4 344 = (4! + √4)? - 4 - (√4)? 345 = (4! + √4)? - 4 - √4 346 = (4! + √4)? - √4 - (√4)? 347 = (4! + √4)? - √4 - √4 348 = (4! + √4)? - ((√4*√4))? 349 = (4! + √4)? - √(√4*√4) 350 = (4! + √4)? -4/4 351 = (4! + √4)? + √4 + √4 - 4 352 = (4! + √4)? + 4/4 353 = (4! + √4)? + 4/√4 354 = ((√4*√4)! + √4)? + (√4)? 355 = (4! + √4)? + √4 + √4 356 = (4! + √4)? + (4?)/√4 357 = (4! + √4)? + 4 + √4 358 = (4! + √4)? + 4 + (√4)? 359 = (4! + √4)? + 4 + 4 360 = (4! + √4)? + (√4)?*(√4)? 361 = ((√4*√4)! + √4)? + 4? 362 = (4! + (√4)?)? - 4*4 363 = (4! + √4)? + 4? + √4 364 = (4! + √4)? + 4? + (√4)? 365 = (4! + √4)? + 4? + 4 366 = (4! + (√4)?)? - 4*(√4)? 367 = (4!)? + (4?)? + 4*(√4)? 368 = (4!)? + (4?)? + 4? + (√4)? 369 = (4!)? + (4?)? + 4? + 4 370 = (4! + (√4)?)? - 4 - 4 371 = (4!)? + (4?)? + 4*4 372 = (4! + (√4)?)? - 4 - √4 373 = (4! + (√4)?)? - √4 - (√4)? 374 = (4! + (√4)?)? - √4 - √4 375 = (4! + (√4)?)? - √[(√4)?*(√4)?] 376 = (4! + (√4)?)? - 4/√4 377 = (4! + (√4)?)? - 4/4 378 = (4! + (√4)?)? + 4 - 4
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Xaphan wrote:
278 = 4 ! * (4 ? + √ 4) –4 ? it's easier
Yes, you're right, that is a lot easier than my way.
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What the... You did to 266 in one night!? That was really, really fast. Well, why not: 267 = 4!*4? + 4! + (√4)? 268 = 4!*4? + 4! + 4 269 = (4?*√4)? + (4?)? + 4 270 = ({[(√4)?]?}?)? + (4+4)? + (√4)? 271 = ({[(√4)?]?}?)? +4*(4?) 272 = 4^4 + 4*4 273 = [(4+√4)?+√4]? - (√4)? 274 = [(4+√4)?+√4]? - √4 275 = ({[(√(√4*√4))?]?}?)? + 44 276 = ((4+√4)?)? +4 -4 277 = 4^4 + (4+√4)? 278 = ({[(√4)?]?}?)? + (4?)? -4 -4 279 = ({[(√4)?]?}?)? + (4?)? -4 -(√4)? 280 = ({[(√4)?]?}?)? + (4?)? -4 -√4 281 = ({[(√4)?]?}?)? + (4?)?- (√4)? - √4 282 = ({[(√4)?]?}?)? + (4?)? -(√4*√4) 283 = ({[(√4)?]?}?)? + (4?)? - (√(√4*√4))? I'm going to school now, but I'll get back to doing this later today. BTW, thanks for finding out the ({[(√4)?]?}?)?, FODA, that helped a lot.
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133 = (4? + sqrt4)? + [(√4*√4)?]? That's it for me for today, I'm gonna go sleep now. See you all later.
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131 = (4?)?*√4 + (4+√4)? 132 = (4? + 4)? + 4! + (√4)?
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Didn't think 128 would be so simple... 130 = (4?)?*√4 + √4*4?
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129 = (4? + 4)? + (√4*√4)!
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122 = √4*((4?)?) + 4? +√4 It's starting to get difficult now... :) BTW, thanks FODA for the telling me about the root-symbol 125 =( 4? + 4)? + √4*4? 126 = (4? + 4)? + 4*4
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121 = (4? + 4)? + (4*4) By the way, how do you do the root-symbols?
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117 = (4? + 4)? + sqrt4 + 4? 118 = (4? + sqrt4)? + 4*(4?) 119 = 4! + (4? + 4)? - 4? 120 = 4!*(4+(4/4))
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111 = (4?)? + (4?)? + (4/4) 112 = (4?)? + (4?)? + 4 - sqrt4 113 = (4? + 4)? + 4 + 4 114 = (4? + sqrt4)? + (4+4)? 115 = (4? + 4)? + (sqrt4+sqrt4)? 116 = (4?)? + (4?)? + 4 + sqrt4
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Bag of Magic Food wrote:
Did anyone post a replacement 31?
Yes, I did that earlier today, but here it is again: 31 = (sqrt4+sqrt4+sqrt4)? + 4? and here's another way to do it: 31 = ((sqrt4+sqrt4)?)? -(sqrt4+sqrt4)! By the way, how far are wo gonna go with this? Not that I mind if we continue or anything, I'm just wondering.
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doh, you were minutes faster Dacicus :)
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69 = (4?)? + 4? +sqrt4 + sqrt4 70 = 4! + 4! + 4! - sqrt4 71 = (4?)? + (sqrt4*sqrt4*4) 72 = (sqrt4+sqrt4)! + 4! + 4! 73 = 4! + (4?)? -4 - sqrt4 74 = 4! + 4! + 4! +sqrt4 75 = (4?)? + (4*4) + 4 76 = 4! + 4! + 4! + 4 77 = (4?+sqrt4)? - (4/4) 78 = (4 + 4 + sqrt4 + sqrt4)? 79 = (4? + sqrt4)? + (4/4) 80 = 4?*(4+sqrt4+sqrt4) 81 = (4?)? + 4! + (4/sqrt4) 82 = (4? + sqrt4)? + sqrt4 + sqrt4 83 = (4?)? + 4! +sqrt4 + sqrt4 84 = (4? + sqrt4)? + 4 + sqrt4 85 = (4?)? + 4? + 4? + 4? 86 = (4? + sqrt4)? + 4 + 4 87 = 4? + 4! + 4 + 4 88 = 4*4*4 + 4! 89 = (4?+4)? - 4*4 90 = (4+4)*(4?) + 4? 91 = (4?)? + (sqrt4+sqrt4+4)? 92 = 4! + (4? + sqrt4)? - 4? 93 = (4?)? + (4+4)? +sqrt4 94 = (4? + sqrt4)? + (4*4) 95 = (4? + sqrt4 + sqrt4) - 4? 96 = (sqrt4 + sqrt4)!*(sqrt4+sqrt4) 97 = (4? + 4)? - 4 - 4 98 = (4? + sqrt4)? +4? + 4? 99 = (4? + sqrt4)? + (4+sqrt4)? 100 = ((4+sqrt4)? + 4)*4 Phew.
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Walker Boh, 4? means 4+3+2+1=10 just as 7? means 7+6+5+4+3+2+1=28 67 = (4?)? +4 +4 +4
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Vatchern wrote:
62 = 4! + 4! + 4! - 4? i think
Yes that is correct, 4! + 4! + 4! - 4? = 24*3 - 10 = 72-10= 62 64 = (sqrt4+sqrt4)*4*4 65 = (4?)? + 4? +4 -4 66 = (4?)? +4? + (4/4)
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Ah, yes you're right. I hate it when I do stuff like that. 55 = (4?)? + (4-4)/4 56 = (4?)? + (sqrt4+sqrt4)/4 57 = (4?)? + (4+4)/4 58 = (4?)? + (4?+sqrt4)/4 59 = (4+4+sqrt4)? + 4 60 = 4! + 4! + 4? + sqrt4 61 = (4?)? + sqrt4 + sqrt4 + sqrt4 62 = (4?+sqrt4)? - 4*4 63 = (4?)? + 4 + sqrt4 + sqrt4