For Super Mario Bros., it's easy. RTA timing starts when 400 appears in 1-1, and ends upon touching the axe (the frame at which TASes of the game usually end). Thus, you take the framecount of the TAS, subtract 197, and divide that by 60.0988139 (approximation of NES' framerate). You end up with RTA timing in seconds.
How can be posible to calculate or know the RTA timing of a TAS?
I want to know.
For Super Mario Bros., it's easy. RTA timing starts when 400 appears in 1-1, and ends upon touching the axe (the frame at which TASes of the game usually end). Thus, you take the framecount of the TAS, subtract 197, and divide that by 60.0988139 (approximation of NES' framerate). You end up with RTA timing in seconds.
Ok, but how do you calculate this: 4:37.626 (the 3 numbers of ms)?
As PP Unknown said, take the framecount of the TAS (16882), subtract 197 to get 16685. Then divide by 60.0988139 to get 277.626111353 seconds (which is 4:37.626).
How can be posible to calculate or know the RTA timing of a TAS?
I want to know.
For Super Mario Bros., it's easy. RTA timing starts when 400 appears in 1-1, and ends upon touching the axe (the frame at which TASes of the game usually end). Thus, you take the framecount of the TAS, subtract 197, and divide that by 60.0988139 (approximation of NES' framerate). You end up with RTA timing in seconds.
Ok, but how do you calculate this: 4:37.626 (the 3 numbers of ms)?
As PP Unknown said, take the framecount of the TAS (16882), subtract 197 to get 16685. Then divide by 60.0988139 to get 277.626111353 seconds (which is 4:37.626).