Posts for FractalFusion


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There's a slight difference between horizontal L. Bolt and zipping horizontally. L. Bolt is either 1 frame faster per 3 frames (when Forte is about to fall out of the ceiling), or 1 frame faster per 7 frames (when not). However, it is possible that the L. Bolt can push Forte into the ceiling where he cannot escape. Forte only goes horizontally with L. Bolt near (but not in) the top of the ceiling. Also, Rockman is slightly different, since he enters corners easier and does not require the menu to enter an upper-left corner. Don't forget that there is also a scroll limit where Forte cannot go past the side of the screen. The scroll limit is 8 pixels/frame, whereas Forte can zip horizontally faster than that. Forte can go above the screen or below the screen (but if he goes below, he dies).
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I'm sure some people prefer that their runs be in Concept Demo because it means that the run is special, and it is so much easier to find.
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Thanks, but we know that trick already. primo isn't making another run with this glitch yet. Apparently, the glitch does not work in Pokemon Yellow.
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I don't like to put stuff on Youtube, so I uploaded it to Filefront instead: http://files.filefront.com/pokemoncardavi/;9320823;/fileinfo.html Note: Video recording starts after the tutorial battle. In fact, this video goes on and beats everyone but the Club Master in the Lightning Club, all with one-move wins. I'll update the movie link above. I won't be working on this for a while.
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Update: 5 battles done, 1.75 clubs beaten (stopped at Lightning Club Master): http://dehacked.2y.net/microstorage.php/info/1357560536/1.75clubsdone%20FractalFusion.vbm Second battle is a two-move win. All other battles are one-move wins. The strategy that I use is based on the fact that the RNG (at CACA-CACB) does not run when changing the deck, and that only index offsets are randomized. Here's my strategy for each battle: 1) Simulate a deck change (to get the proper RNG values after changing it for real). 2) Enter battle and check C480 for the opponent's cards. Make note of all Basic Pokemon cards and also note which ones are weak (i.e. the target cards). 3) Check each frame and look at C37E for the opponent's starting hand. Ideally, I want a hand that has as few (but greater than zero) target Basic Pokemon as possible (either 1 or 2), and no others. 4) Play on to get information such as coin flips. 5) When I am satisfied with the event, go back to the frame with which I started battle. Check CACA and write down the 3-byte sequence. Then play on a bit and then go to C27E for my starting hand and opening draw card. 6) Return to the deck change screen and modify the deck such that the desired cards fall in the index offsets specified in step 5. 7) Trigger the battle on the desired RNG number and beat the opponent. The deck order (to where index offsets refer) is listed at C400. When adding cards, they are appended to the end. When deleting cards, the first instance is deleted and the remaining cards are shifted left. It is possible to intentionally redraw the hand (by not getting Basic Pokemon) to manipulate the coin toss. Also, against special opponents (the Club Masters, Ronald, and probably the Grand Masters), the game basically hacks the draw in their favor, giving them a hand with at least two Basic Pokemon and some energy cards. It occurs just before placing prizes. Since I can't win in less than two moves, I can rely on the prizes for a card which can be used on the second turn. Also, redrawing the hand may mess with their Basic Pokemon. Useful cards: Nidoran Male (1 energy, 30 damage on coin flip), Hitmonchan (1 energy, 20 damage), Pluspower (10 extra damage), Defender (prevents opponent attack which takes time), Energy Search (shuffling deck changes random map completely).
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We believe mathematical entities to exist when we feel the need for them to exist, that they have a special meaning. History has shown that acceptance of new concepts was slow. This includes negative numbers, rational numbers, irrational numbers, complex numbers, infinity. Yes, the concept of complex numbers was so bizarre at the time that they were (and still are, to some extent) called "imaginary numbers". Not only that, but by Cantor's logic, there are different types of infinities and one infinity can be greater than another. P.S. About the X=Y=infinity thing, infinity minus infinity (or infinity plus negative infinity) is 'defined' not to exist (in other words, not defined). Any attempt to define it so far results in chaos (or so (I think) most mathematicians believe). Note the word 'believe'.
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√x is the least upper bound on all rational numbers whose square is less than x. P.S. Such l.u.b. is greater than negative infinity (in other words, real) because there exists at least one rational number whose square is less than x, namely 0. Even if real numbers are defined as a limit of a rational sequence, there is a rational sequence converging to √x since the rational numbers are dense on any interval, and the square function is continuous.
Editor, Experienced Forum User, Published Author, Skilled player (1941)
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VBA v17.1 (or v17) is not on the first post of the sticky topic. I set up a link for VBA v17 at Emulator Homepages below. Hopefully it works (assuming that you wanted to watch the Pokemon Gold run). http://tasvideos.org/EmulatorHomepages.html
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I don't know. Sometimes, I fix the problem (for Sapphire and Emerald) without knowing exactly how it was done. It may help to set Save Type as Flash 128K.
Editor, Experienced Forum User, Published Author, Skilled player (1941)
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nfq wrote:
infinity does not exist...
Infinity exists in your head. Maybe not you personally. Even 0, 1, 2, -1, 1/2, sqrt(2), sqrt(-1), are all entities of our imagination.
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HHS wrote:
Choose a coordinate system such that the first point is located at (1,0,0) and the second at (x,y,z). The distance from the first point to the second point is sqrt((x-1)^2+1-x^2) = sqrt(2-2x). We must then calculate the integral of sqrt(2-2X)dP(x<X) with X going from -1 to 1. The distance sqrt(1-x^2) shall be called r and we note that dr/dx = -x/r. The surface area of the portion of the sphere for which X ≤ x ≤ X+dX is 2*pi*r*sqrt(dX^2+dr^2) = 2*pi*r*sqrt((1+X^2/r^2)dX^2) = 2*pi*r*sqrt(dX^2/r^2) = 2*pi*dX. Therefore, dP(x<X) = 1/2dX. The answer becomes (4^(3/2)*2/3)/2 = 8/3.
Hmm. I think you're off by a factor of 2 (during the integration). It should be 4/3. I came up with 4/3 by starting with an angle theta between the two points, and that the probability of a point being at angle theta is sin(theta)/2. The rest is similar to what HHS wrote.
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Sir VG wrote:
NrgSpoon wrote:
I believe the damage during these parts were to build weapon energy, since there's a shop item that will do this.
Must have missed it then. If there's a reason, that's fine. Wish there was a slightly more "professional" way to go about it though, but meh. ^^;;
No, it's because of Counter Attack (against bosses, 2 more damage per hit when at 7 HP or less).
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Various wobble scores for some SNES games (sorry for the nondescript names): alttp 10035 yoshis island 3183 super metroid 100% 2535 alttp glitched 2369 mario kart 1073 mega man x 735 yoshis island glitch 381 rockman7 222 donkey kong country 101% 210 rnf 118 mario world small 101 mega man x2 88 rnf100 55 chrono trigger 53 mega man x x2 41 super street fighter II zangief 21 mega man x3 15 mario world 13 mario world 96e 12 super metroid min 1 super street fighter II ken 0 mario rpg 0 left-right-left counts as 1 point right-left-right counts as 1 point (left+right)=right
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If you didn't like the damage taken in this run, do not hope. I am taking even more damage in my run. From the fourth Robot Master on, I take at least 21 (out of 28) damage in every level with a boss. Reason: Counter Attack. Does 2 extra damage per hit when Rockman/Forte is at 7 or lower. I don't think many viewers want to see boss battles twice as long. This run impressed me greatly. While Rockman did not have double-jump, he was able to enter corners easier than Forte could.
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Teleport stage done. I saved 31 frames in the level, more than on Cold Man's stage. The runs are now at the same point. I forgot to figure out last time, but my run is now about 100s (1m 40s) faster.
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It actually works in PAL (as well as NTSC) mode, although that should not change the verdict.
Editor, Experienced Forum User, Published Author, Skilled player (1941)
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I successfully hex-edited Burner Man level and Tengu Man level improvements, saving about 3 seconds. The Tengu Man improvement was only 21 frames, but it looks better [/personalopinion].
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sgrunt wrote:
There exist irrational numbers such that the (2n)-th decimal digit is also that of pi, whereas the (2n-1)th digit does not. The map you describe would map all of these numbers to the same irrational number and therefore is not bijective.
Note that the (2n)-th decimal digit of y is the n-th decimal digit of x, not the (2n)-th decimal digit of x. I ensure all the digits of x are used here. This type of decimal place weaving comes from set theory, where it is possible to show that the cardinality of R^n (set of n-tuples of real numbers) and R (set of real numbers) are the same.
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Warp wrote:
What is a subset of the real numbers that has no interior points?
Interior point Basically, x is an interior point of a real subset A if there exists an interval of positive width (however small) centered on x that is (completely) contained in A. e.g. The set of interior points of closed interval [0,1] is open interval (0,1). The set of interior points of the set of irrational numbers is empty. There are no interior points, because every interval of positive width contains a rational number. P.S. I had to check Wikipedia for the definition as well.
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HHS wrote:
Here's one. Find an a bijective map from the real numbers to a subset of the real numbers that has no interior points.
Define f: real number x maps to y as follows: - the integer part of y is the integer part of x - for the fractional part of y: -- the (2n)-th decimal digit of y is the n-th decimal digit of x, n>=1 -- the (2n-1)-th decimal digit of y is the n-th decimal digit of pi, n>=1 Then f is a bijective map from the real numbers to a subset of the irrational numbers A. The set of irrational numbers has no interior points. Therefore, A has no interior points.
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Magic Man done: http://dehacked.2y.net/microstorage.php/info/183190020/Rockman%20%26%20Forte%20%28J%29%20FractalFusion.smv Unfortunately, I guess that I saved very little time in Magic Man. The one zipping glitch I did did not contribute a lot. Yes, I took damage intentionally. Finding weapon energy for Tengu Blade was also hard. One thing I found was that completely splitting Spread Drill throws 13-15 random numbers. That can help matters somewhat. I can tell you that getting the necessary weapon energy during the fortress stages will be at least 10x harder. No, I do not have Energy Saver.
parrot14green wrote:
A few improvements. 49 frames gained in burnerman level.
Looks good. I'll see if I can insert these tricks into the run.
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Yes. P.S. I'm being honest here. Real life should be more important. Come to think of it, a lot of internet users take real-life escape way too far.
Editor, Experienced Forum User, Published Author, Skilled player (1941)
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The rule is probably enforced on other forums because a lot of "goodbye" threads are troll threads. There's at least one such thread on this forum, but I won't link to it.
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Tengu Man done. ~12 seconds saved, for a total of about 1:30.
Comicalflop wrote:
I just wonder if Rockman can perform the same glitches with ice wall and such as easily (or at all), especially since he lacks a double jump.
Probably. Rockman has some trouble reaching positions that Forte can easily reach, though it can be done with Ice Wall and cancel.
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The missed shots are for luck-manipulation. Every shot throws one random value. Strangely, if it hits a wall, it throws another. It's far more convenient than in the X series, where you have to drag X down a wall to throw a random value (although luck is timing-dependent in that one). I don't know yet about whether I will do a Rockman version. Maybe the 100 CD run?