I know this seems like it's not a big deal
"tutorial%"
The desired ROM filename should be last.
If you want TASes to be at GDQs, prove they can be successful cause so far the evidence doesn't suggest they really can.
i thought the point of tas was to make cool looking play through
This seems paradoxical. The universe could end before the photon reaches its target, yet from its own perspective it reaches the target in 0 seconds.
Note that the strategies above are optimal but it may be possible that they aren't unique, though my guess is that they are unique.
CPU: AMD FX-9590 4.7GHz 8-core CPU Instructions: MMX(+), SSE, SSE2, SSE3, SSSE3, SSE4.1, SSE4.2, SSE4A, x86-64, AMD-V, AES, AVX, XOP, FMA3, FMA4 Motherboard: Asus SABERTOOTH 990FX R2.0 GPU: nVidia GTX 750Ti SC 2GB GFX Drivers: Nvidia v385.69 OS: Windows 7 Ultimate 64-bit SP1 RAM: 16GB Kingston 1866MHz DDR3
Some of the worst cases I have seen were like a 10-minute video to explain something that could have literally been explained with a relatively short paragraph of text. [...] This appears to have become more and more common recently.
(and in my hastiness figuring out lsnes, I've created the movie starting from dirty SRAM accidentally)
are my 2 answers not exact enough? :o
Arguments a and b are strings in base base. The base is optional and 10 if not given. The result is a string in base base. Example: mult("B65698F7","41C64E6D",16) gives "2ED93BAD0B84632B". The last 32 significant bits are just the last 8 characters, so result = mult("B65698F7","41C64E6D",16) print(result:sub(-8)) gives 0B84632B. (Additional symbols have to be added to chars for higher bases than 16).Language: lualocal chars = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"} function add(a,b,base) base = base or 10 local ret = "" while a:sub(1,1)==chars[1] and #a>1 do a=a:sub(2) end while b:sub(1,1)==chars[1] and #b>1 do b=b:sub(2) end while #a<#b do a=chars[1]..a end while #b<a>= base then cur = cur - base c = true end ret = chars[cur+1]..ret end if c then ret = chars[2]..ret end return ret end function mult(a,b,base) base = base or 10 local ret = "" while #a<#b do a=chars[1]..a end while #b<#a do b=chars[1]..b end for i = 1,#a do ret = ret..chars[1] for i=1,tonumber(a:sub(i,i),base) do ret = add(ret,b,base) end end return ret end